画像 if x^p^q=(x^p)^q then p= 158680-If x^py^q=(x+y)^p+q then dy/dx
Answer to Solved If p(x) and q(x) are arbitrary polynomials of degree Math;P^x = q & q^y = r => (p^x)^y = r & r^z = p^6 => { (p^x)^y}^z =p^6 => p^xyz = p^6 comparing powers on both sides xyz = 6 mark as brainliast if it helpedUsing the operations $\lnot$, $\land$, $\lor$, $\implies$, $\Leftrightarrow$, we can construct compound expressions such as $$ (P\land (\lnot Q))\implies ((\lnot R)\lor ((\lnot P)\land Q)) $$ Solved Put The Steps In Correct Order To Prove That If X Is Irrational Then Ixis Irrational Using Contraposition Rank The Options Below If Vx Is Rational Then Ix Plq For Some If x^py^q=(x+y)^p+q then dy/dx